[3d Max 7}Charriot anim

usuarioeco · 30-06-2005, 07:32 PM

Hello! My english is very bad, but i´ll try to explain what i need. I want to do an animation of a charriot with chess horses. They have only one foot. I do the anim of the horses jumping in place, and now i need a script or something that when i move the charriot : 1- the wheels spin(or twirl?) and 2- the charriot stay in touch with the terrain made with a plane with noise applied to make the mounts and valleys.
I hope you can understand my ugly english and that someone can help me.
Thanks in advance for everyone.

MaggieQue · 01-07-2005, 12:41 AM

Ok, so u need the wheels keep spinning when the horse running. And animation of charriot moves on a bumpy road?

usuarioeco · 01-07-2005, 12:52 AM

Yes Maggie! The road is bumpy, but not much. The mountas are big in area but not to high

MaggieQue · 02-07-2005, 04:37 PM

Here's my chariot, when it moved forward it looks bumpy, but moved backward smoothly.

MaggieQue · 03-07-2005, 03:42 AM

First, we link the 2 wheels to the carrier.

MaggieQue · 03-07-2005, 03:43 AM

Right click left wheel > Click Wire Parameters > Transform > Rotation > Y Rotation, while dragging

the dotted line, click the carrier > Transform > Position > Position X.

MaggieQue · 05-07-2005, 01:31 AM

How about this?

MaggieQue · 05-07-2005, 10:12 AM

Some steps:

1. Link Carrier to Dummy.

2. Select Dummy > Animation Menu> Constraints > Path Constraint> Click ur spline path. Now the chariot moves along the path.

3. Input curvelength $Helix01 at MaxScript Mini Listener, then press enter. This is the value of the spline length. I call it CurveLength. (Helix01 is my spline that is used as a path, if ur path is called spline01, then use $spline01)

4. Wire Wheel01 Y rotation to Dummy Position > Path Constraint > Percent.

5. Input degtorad(-Percent*CurveLength) at Wheel01. 2305.68 is my CurveLength.

MaggieQue · 05-07-2005, 10:20 AM

Here's a screenshot. The dummy has to be placed between the 2 wheels, and it's pivot point is exactly "on the ground".

Maybe u could try

CurveLength*degtorad(-Percent)

It gives the same result too.

usuarioeco · 05-07-2005, 07:18 PM

OK Maggie, i´ll try and then i return with a feedback to you, ok?
Tanx again, and again, sorry for my ugly english!

migelowsky · 06-07-2005, 05:03 AM

wow, you muss summit this to the tutorial section Maggie =)

MaggieQue · 05-07-2005, 07:51 PM

Ur English is quite beautiful. Don't worry. I speak broken English too. Luv Luv kissy kissy.

30-06-2005, 07:32 PM	#1
usuarioeco Registered User Join Date: Apr 2005 Posts: 8 Thanks: 0 Thanked 0 Times in 0 Posts	[3d Max 7}Charriot anim Hello! My english is very bad, but i´ll try to explain what i need. I want to do an animation of a charriot with chess horses. They have only one foot. I do the anim of the horses jumping in place, and now i need a script or something that when i move the charriot : 1- the wheels spin(or twirl?) and 2- the charriot stay in touch with the terrain made with a plane with noise applied to make the mounts and valleys. I hope you can understand my ugly english and that someone can help me. Thanks in advance for everyone.

01-07-2005, 12:41 AM	#2
MaggieQue Registered User Join Date: Apr 2005 Location: Singapore Posts: 2,326 Thanks: 0 Thanked 0 Times in 0 Posts Awards Showcase Total Awards: 3	Ok, so u need the wheels keep spinning when the horse running. And animation of charriot moves on a bumpy road? __________________ My Homepage CandyGirl.2ya.com My Singapore Cross-Stitch Meetup Group

01-07-2005, 12:52 AM	#3
usuarioeco Registered User Join Date: Apr 2005 Posts: 8 Thanks: 0 Thanked 0 Times in 0 Posts	Bumpy road! Yes Maggie! The road is bumpy, but not much. The mountas are big in area but not to high Last edited by usuarioeco; 01-07-2005 at 06:05 PM..

02-07-2005, 04:37 PM	#4
MaggieQue Registered User Join Date: Apr 2005 Location: Singapore Posts: 2,326 Thanks: 0 Thanked 0 Times in 0 Posts Awards Showcase Total Awards: 3	Here's my chariot, when it moved forward it looks bumpy, but moved backward smoothly. __________________ My Homepage CandyGirl.2ya.com My Singapore Cross-Stitch Meetup Group

03-07-2005, 03:42 AM	#5
MaggieQue Registered User Join Date: Apr 2005 Location: Singapore Posts: 2,326 Thanks: 0 Thanked 0 Times in 0 Posts Awards Showcase Total Awards: 3	First, we link the 2 wheels to the carrier. __________________ My Homepage CandyGirl.2ya.com My Singapore Cross-Stitch Meetup Group

03-07-2005, 03:43 AM	#6
MaggieQue Registered User Join Date: Apr 2005 Location: Singapore Posts: 2,326 Thanks: 0 Thanked 0 Times in 0 Posts Awards Showcase Total Awards: 3	Right click left wheel > Click Wire Parameters > Transform > Rotation > Y Rotation, while dragging the dotted line, click the carrier > Transform > Position > Position X. __________________ My Homepage CandyGirl.2ya.com My Singapore Cross-Stitch Meetup Group

05-07-2005, 01:31 AM	#7
MaggieQue Registered User Join Date: Apr 2005 Location: Singapore Posts: 2,326 Thanks: 0 Thanked 0 Times in 0 Posts Awards Showcase Total Awards: 3	How about this?

05-07-2005, 10:12 AM	#8
MaggieQue Registered User Join Date: Apr 2005 Location: Singapore Posts: 2,326 Thanks: 0 Thanked 0 Times in 0 Posts Awards Showcase Total Awards: 3	Some steps: 1. Link Carrier to Dummy. 2. Select Dummy > Animation Menu> Constraints > Path Constraint> Click ur spline path. Now the chariot moves along the path. 3. Input curvelength $Helix01 at MaxScript Mini Listener, then press enter. This is the value of the spline length. I call it CurveLength. (Helix01 is my spline that is used as a path, if ur path is called spline01, then use $spline01) 4. Wire Wheel01 Y rotation to Dummy Position > Path Constraint > Percent. 5. Input *degtorad(-PercentCurveLength)** at Wheel01. 2305.68 is my CurveLength. Last edited by MaggieQue-3DT; 05-07-2005 at 10:22 AM..

05-07-2005, 10:20 AM	#9
MaggieQue Registered User Join Date: Apr 2005 Location: Singapore Posts: 2,326 Thanks: 0 Thanked 0 Times in 0 Posts Awards Showcase Total Awards: 3	Here's a screenshot. The dummy has to be placed between the 2 wheels, and it's pivot point is exactly "on the ground". Maybe u could try CurveLengthdegtorad(-Percent) It gives the same result too. Last edited by MaggieQue-3DT; 05-07-2005 at 02:26 PM..*

05-07-2005, 07:18 PM	#10
usuarioeco Registered User Join Date: Apr 2005 Posts: 8 Thanks: 0 Thanked 0 Times in 0 Posts	Tanx again!!!! OK Maggie, i´ll try and then i return with a feedback to you, ok? Tanx again, and again, sorry for my ugly english!

06-07-2005, 05:03 AM	#11
migelowsky Banned. Join Date: Mar 2005 Posts: 486 Thanks: 0 Thanked 0 Times in 0 Posts	wow, you muss summit this to the tutorial section Maggie =)

05-07-2005, 07:51 PM	#12
MaggieQue Registered User Join Date: Apr 2005 Location: Singapore Posts: 2,326 Thanks: 0 Thanked 0 Times in 0 Posts Awards Showcase Total Awards: 3	Ur English is quite beautiful. Don't worry. I speak broken English too. Luv Luv kissy kissy.

Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)

Thread Tools
Show Printable Version Email this Page
Display Modes
Switch to Linear Mode Hybrid Mode Switch to Threaded Mode